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Preparation and Reactions of Ethers

Ethers are prepared by methods such as Williamson synthesis and undergo cleavage with hydrogen halides to form alcohols and alkyl halides, depending on the structure of the ether.

In one line: Williamson likes primary halides; HI opens ethers at the alkyl side.

Practice This Concept

Understand it

  • In Williamson synthesis, an alkoxide ion reacts with a primary alkyl halide through nucleophilic substitution to form an ether.
  • This method works best with primary alkyl halides because secondary and tertiary halides may favour elimination.
  • Ethers are generally less reactive than alcohols, but strong hydrogen halides such as HI or HBr cleave the C-O bond.
  • In unsymmetrical ethers, cleavage depends on the nature of the alkyl groups and reaction conditions; aryl-alkyl ethers usually cleave at the alkyl-oxygen bond because the aryl-oxygen bond has partial double-bond character.

Example

Sodium ethoxide reacts with methyl iodide to give methoxyethane. Anisole with HI gives phenol and methyl iodide.

Rule to remember

Williamson pattern: RONa + R'X gives ROR' + NaX, best when R'X is primary.

Ether cleavage pattern: ROR' + HX gives an alcohol or phenol plus an alkyl halide; excess HX can convert alcohol further to halide.

See it worked out

Follow the example line by line, then use the same method on new questions.

Worked example

  1. 1Plan synthesis of ethoxyethane by Williamson method.
  2. 2Use sodium ethoxide and bromoethane; ethoxide attacks the primary ethyl halide and forms CH3CH2OCH2CH3.

Method you can reuse

  1. 1For preparation, choose an alkoxide and a primary alkyl halide.
  2. 2For cleavage, identify whether the ether is dialkyl or aryl-alkyl, mark the weaker or more reactive C-O bond, then apply HX cleavage logic.

Visual tip

A bond-cleavage diagram marking the alkyl-oxygen bond is useful for anisole and unsymmetrical ether questions.

Check yourself

Answer the question in your head before opening the answer.

Try it yourself

Why is chlorobenzene not a good alkyl halide component for Williamson ether synthesis?

Think first, then show answer
The aryl C-Cl bond is not suitable for normal nucleophilic substitution under these conditions, so aryl halides do not behave like primary alkyl halides.

Common wrong answer

Predicting iodobenzene from anisole and HI is wrong in the usual school-level treatment; cleavage occurs at the methyl-oxygen bond to give phenol and methyl iodide.

Don't mix this up

A common error is using a tertiary alkyl halide in Williamson synthesis and expecting clean ether formation.

Exam tip

For Williamson synthesis, put the more hindered group in the alkoxide part and use a primary alkyl halide when possible.

Write it in the exam

Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.

How CBSE asks it

It is asked as synthesis planning, product of HI or HBr cleavage, reason for failure with tertiary halides, and naming of ethers.
  1. 1

    Enough for 1 mark

    Ethers are prepared by methods such as Williamson synthesis and undergo cleavage with hydrogen halides to form alcohols and alkyl halides, depending on the structure of the ether.

  2. 2

    Add for 2 marks

    Example: Sodium ethoxide reacts with methyl iodide to give methoxyethane. Anisole with HI gives phenol and methyl iodide.

  3. 3

    Add for 3 marks

    In Williamson synthesis, an alkoxide ion reacts with a primary alkyl halide through nucleophilic substitution to form an ether.

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