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Standard Integrals of Particular Forms

Integrals of particular forms are standard results for expressions such as 1/(x^2+a^2), 1/(x^2-a^2), 1/√(a^2-x^2), and related algebraic forms.

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Student-friendly explanation

These forms are solved by recognizing the exact structure and matching it with the correct standard formula. The sign between terms and the square-root placement decide whether the result involves tan inverse, sine inverse, logarithm, or another standard expression.

How to write this in exams

  1. 1

    Start with the exact idea

    Integrals of particular forms are standard results for expressions such as 1/(x^2+a^2), 1/(x^2-a^2), 1/√(a^2-x^2), and related algebraic forms.

  2. 2

    Then show how to use it

    Identify the exact form. Rewrite constants as squares. Check whether the expression is x^2+a^2, a^2-x^2, x^2-a^2, or a^2+x^2. Apply the matching formula. Include absolute value in logarithmic forms where required. Add +C for indefinite integrals.

  3. 3

    Add one concrete example

    ∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C for a>0.

  4. 4

    Avoid this incomplete answer

    For ∫dx/(x^2-9), writing (1/3)tan^(-1)(x/3)+C instead of the logarithmic form because the minus sign was ignored.

Definition

Integrals of particular forms are standard results for expressions such as 1/(x^2+a^2), 1/(x^2-a^2), 1/√(a^2-x^2), and related algebraic forms.

Example

∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C for a>0.

Rule to remember

Key forms for a>0: ∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C; ∫dx/√(a^2-x^2)=sin^(-1)(x/a)+C; ∫dx/(x^2-a^2)=(1/(2a))ln|(x-a)/(x+a)|+C; ∫dx/(a^2-x^2)=(1/(2a))ln|(a+x)/(a-x)|+C. Conditions and signs must be checked.

Memory hook

Plus with squares often leads to tan inverse; square root of a^2 minus x^2 leads to sine inverse.

Examples and method

Worked example

Evaluate ∫dx/(x^2+25). Here x^2+25=x^2+5^2. Using ∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C, the answer is (1/5)tan^(-1)(x/5)+C.

Method to apply

Identify the exact form. Rewrite constants as squares. Check whether the expression is x^2+a^2, a^2-x^2, x^2-a^2, or a^2+x^2. Apply the matching formula. Include absolute value in logarithmic forms where required. Add +C for indefinite integrals.

Diagram support

A diagram is generally not needed. Formula recognition, sign checking, and constant-square rewriting are the useful supports.

How CBSE asks it

Often asked as direct standard-form questions or after completing the square. May also appear inside substitution-based integrals where the transformed integral matches a standard form.

Avoid common mistakes

Common confusion

A frequent mistake is confusing x^2+a^2 with a^2-x^2 and using tan inverse when sine inverse is required.

Common wrong answer

For ∫dx/(x^2-9), writing (1/3)tan^(-1)(x/3)+C instead of the logarithmic form because the minus sign was ignored.

Exam tip

Match the denominator exactly before applying a formula. Rewrite constants as squares whenever possible, such as x^2+9=x^2+3^2.

Quick check

Evaluate ∫dx/√(16-x^2).

sin^(-1)(x/4)+C, using ∫dx/√(a^2-x^2)=sin^(-1)(x/a)+C with a=4.

Answer writing and exam use

1-mark answer

Integrals of particular forms are standard results for expressions such as 1/(x^2+a^2), 1/(x^2-a^2), 1/√(a^2-x^2), and related algebraic forms.

2-mark answer

Integrals of particular forms are standard results for expressions such as 1/(x^2+a^2), 1/(x^2-a^2), 1/√(a^2-x^2), and related algebraic forms. Key forms for a>0: ∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C; ∫dx/√(a^2-x^2)=sin^(-1)(x/a)+C; ∫dx/(x^2-a^2)=(1/(2a))ln|(x-a)/(x+a)|+C; ∫dx/(a^2-x^2)=(1/(2a))ln|(a+x)/(a-x)|+C. Conditions and signs must be checked. ∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C for a>0.

3-mark answer

These forms are solved by recognizing the exact structure and matching it with the correct standard formula. The sign between terms and the square-root placement decide whether the result involves tan inverse, sine inverse, logarithm, or another standard expression. Key forms for a>0: ∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C; ∫dx/√(a^2-x^2)=sin^(-1)(x/a)+C; ∫dx/(x^2-a^2)=(1/(2a))ln|(x-a)/(x+a)|+C; ∫dx/(a^2-x^2)=(1/(2a))ln|(a+x)/(a-x)|+C. Conditions and signs must be checked. Evaluate ∫dx/(x^2+25). Here x^2+25=x^2+5^2. Using ∫dx/(x^2+a^2)=(1/a)tan^(-1)(x/a)+C, the answer is (1/5)tan^(-1)(x/5)+C. Often asked as direct standard-form questions or after completing the square. May also appear inside substitution-based integrals where the transformed integral matches a standard form. For ∫dx/(x^2-9), writing (1/3)tan^(-1)(x/3)+C instead of the logarithmic form because the minus sign was ignored.
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