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Equation of a Line in Vector and Cartesian Form

A line in space is determined by one point on the line and one direction vector. Its vector form is r = a + λb, where a is the position vector of a fixed point and b is a direction vector.

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Student-friendly explanation

In vector form, r represents the position vector of any variable point on the line, a represents a known point on the line, b gives the direction, and λ is a real parameter. If the line passes through (x₁, y₁, z₁) and has direction ratios a, b, c, its Cartesian symmetric form is (x - x₁)/a = (y - y₁)/b = (z - z₁)/c, provided the relevant denominators are handled correctly.

How to write this in exams

  1. 1

    Start with the exact idea

    A line in space is determined by one point on the line and one direction vector. Its vector form is r = a + λb, where a is the position vector of a fixed point and b is a direction vector.

  2. 2

    Then show how to use it

    First identify a point on the line. Next find or read the direction ratios. If two points are given, subtract corresponding coordinates to get direction ratios. Write vector form using position vector plus λ times direction vector. Convert to Cartesian form by equating each coordinate expression to the same parameter.

  3. 3

    Add one concrete example

    The line through (1, -2, 3) with direction ratios 2, 1, -4 is r = i - 2j + 3k + λ(2i + j - 4k), or (x - 1)/2 = (y + 2)/1 = (z - 3)/(-4).

  4. 4

    Avoid this incomplete answer

    For points A(1,2,-3) and B(3,1,1), writing direction ratios as (-2,1,-4) is acceptable only if used consistently, but mixing this with point B and signs from point A can produce a different line expression with errors.

Definition

A line in space is determined by one point on the line and one direction vector. Its vector form is r = a + λb, where a is the position vector of a fixed point and b is a direction vector.

Example

The line through (1, -2, 3) with direction ratios 2, 1, -4 is r = i - 2j + 3k + λ(2i + j - 4k), or (x - 1)/2 = (y + 2)/1 = (z - 3)/(-4).

Rule to remember

Vector form: r = a + λb. Cartesian form: (x - x₁)/a = (y - y₁)/b = (z - z₁)/c. Condition for use: (x₁, y₁, z₁) must be a point on the line and a, b, c must be direction ratios of the line. If any direction ratio is 0, the corresponding coordinate remains constant instead of being placed over 0 in ordinary symmetric form.

Memory hook

A space line needs a starting point and a direction arrow.

Examples and method

Worked example

Find the line through A(1, 2, -3) and B(3, 1, 1). Direction ratios from A to B are (3 - 1, 1 - 2, 1 - (-3)) = (2, -1, 4). Vector form: r = i + 2j - 3k + λ(2i - j + 4k). Cartesian form: (x - 1)/2 = (y - 2)/(-1) = (z + 3)/4.

Method to apply

First identify a point on the line. Next find or read the direction ratios. If two points are given, subtract corresponding coordinates to get direction ratios. Write vector form using position vector plus λ times direction vector. Convert to Cartesian form by equating each coordinate expression to the same parameter.

Diagram support

A 3D axes diagram with one fixed point and a direction arrow supports the idea of generating all points on the line by changing λ.

How CBSE asks it

Questions ask students to form the equation from a point and direction, from two points, or convert between vector and Cartesian forms. Longer problems may use the line equation before finding angles or distances.

Avoid common mistakes

Common confusion

A common error is using the coordinates of the point as direction ratios or changing signs incorrectly while forming x - x₁, y - y₁, z - z₁.

Common wrong answer

For points A(1,2,-3) and B(3,1,1), writing direction ratios as (-2,1,-4) is acceptable only if used consistently, but mixing this with point B and signs from point A can produce a different line expression with errors.

Exam tip

Before writing the equation, underline the point and circle the direction vector or direction ratios. This prevents mixing their roles.

Quick check

Write the vector equation of the line through (2, 0, -1) and parallel to 3i - j + 2k.

r = 2i - k + λ(3i - j + 2k), where λ is real.

Answer writing and exam use

1-mark answer

A line in space is determined by one point on the line and one direction vector. Its vector form is r = a + λb, where a is the position vector of a fixed point and b is a direction vector.

2-mark answer

A line in space is determined by one point on the line and one direction vector. Its vector form is r = a + λb, where a is the position vector of a fixed point and b is a direction vector. Vector form: r = a + λb. Cartesian form: (x - x₁)/a = (y - y₁)/b = (z - z₁)/c. Condition for use: (x₁, y₁, z₁) must be a point on the line and a, b, c must be direction ratios of the line. If any direction ratio is 0, the corresponding coordinate remains constant instead of being placed over 0 in ordinary symmetric form. The line through (1, -2, 3) with direction ratios 2, 1, -4 is r = i - 2j + 3k + λ(2i + j - 4k), or (x - 1)/2 = (y + 2)/1 = (z - 3)/(-4).

3-mark answer

In vector form, r represents the position vector of any variable point on the line, a represents a known point on the line, b gives the direction, and λ is a real parameter. If the line passes through (x₁, y₁, z₁) and has direction ratios a, b, c, its Cartesian symmetric form is (x - x₁)/a = (y - y₁)/b = (z - z₁)/c, provided the relevant denominators are handled correctly. Vector form: r = a + λb. Cartesian form: (x - x₁)/a = (y - y₁)/b = (z - z₁)/c. Condition for use: (x₁, y₁, z₁) must be a point on the line and a, b, c must be direction ratios of the line. If any direction ratio is 0, the corresponding coordinate remains constant instead of being placed over 0 in ordinary symmetric form. Find the line through A(1, 2, -3) and B(3, 1, 1). Direction ratios from A to B are (3 - 1, 1 - 2, 1 - (-3)) = (2, -1, 4). Vector form: r = i + 2j - 3k + λ(2i - j + 4k). Cartesian form: (x - 1)/2 = (y - 2)/(-1) = (z + 3)/4. Questions ask students to form the equation from a point and direction, from two points, or convert between vector and Cartesian forms. Longer problems may use the line equation before finding angles or distances. For points A(1,2,-3) and B(3,1,1), writing direction ratios as (-2,1,-4) is acceptable only if used consistently, but mixing this with point B and signs from point A can produce a different line expression with errors.
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