de Broglie Hypothesis: Wave Nature of Matter
The de Broglie hypothesis states that every moving material particle is associated with a matter wave whose wavelength is λ = h/p, where p is the momentum of the particle.
In one line: Matter wavelength becomes visible when momentum becomes tiny.
Concept Practice Coming SoonUnderstand it
- Light shows both wave and particle behaviour, and de Broglie proposed that moving particles should also show wave behaviour.
- For a non-relativistic particle of mass m moving with speed v, p = mv, so λ = h/mv.
- The wavelength is noticeable for microscopic particles such as electrons but extremely small for everyday objects because their momentum is large.
- Electron diffraction provides evidence for the wave nature of matter.
Example
Formula and rule
de Broglie wavelength: λ = h/p.
For a non-relativistic particle, λ = h/mv.
For a charged particle accelerated through potential V, kinetic energy qV = p2/(2m), so λ = h/√2mqV.
For an electron, q = e.
SI units: λ in m, h in J s, p in kg m s−1, m in kg, v in m s−1, q in C, and V in volt.
Use only when the particle is moving and non-relativistic conditions are assumed for mv form.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
An electron is accelerated through 100 V.
- 1Using λ = h/√2meV, λ = (6.63 × 10−34)/√(2 × 9.11 × 10−31 × 1.6 × 10−19 × 100).
- 2The denominator is about 5.40 × 10−24 kg m s−1, so λ = 1.23 × 10−10 m.
- 3This wavelength is of atomic size, so electron diffraction is possible.
Method you can reuse
Visual tip
For Davisson-Germer evidence, a diagram may show an electron beam incident on a nickel crystal, scattered electrons, detector, and intensity variation with angle. For formula use, a wave drawn along the particle path can support the idea.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
Why is de Broglie wavelength not observed for a moving cricket ball in ordinary conditions?
Think first, then show answerHide answer
Common wrong answer
Wrong: A particle at rest has a de Broglie wavelength h/m. Correct: de Broglie wavelength is associated with momentum; if p = 0, λ = h/p is not meaningful as a finite matter wavelength for motion.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
The de Broglie hypothesis states that every moving material particle is associated with a matter wave whose wavelength is λ = h/p, where p is the momentum of the particle.
- 2
Add for 2 marks
Example: An electron accelerated through a potential difference has a measurable de Broglie wavelength, which allows electron beams to produce diffraction patterns from crystals.
- 3
Add for 3 marks
Light shows both wave and particle behaviour, and de Broglie proposed that moving particles should also show wave behaviour.
Concept practice is coming soon
Login to access concept-level MCQs and weak-concept practice as they become available.
Help improve this page
Found something confusing, incorrect, or missing?