Lorentz Force on a Moving Charge
Lorentz force is the total force on a charge q moving with velocity v in the presence of electric field E and magnetic field B, given by F = q(E + v × B).
In one line: Magnetic force turns the velocity; it does not pull along the velocity.
Concept Practice Coming SoonUnderstand it
- The electric part qE acts whether the charge is moving or at rest.
- The magnetic part q(v × B) acts only when the charge has velocity with a component perpendicular to the magnetic field.
- Its direction is perpendicular to both v and B, and it is reversed for a negative charge.
- If v is perpendicular to B and there is no electric field, the magnetic force provides centripetal force, so the charge moves in a circular path.
Example
Formula and rule
F = q(E + v × B).
Magnetic force magnitude: FB = qvB sin θ.
For perpendicular entry into uniform B: qvB = mv2/r, so r = mv/(qB) using magnitude of q. q is in coulomb, v in m s−1, B in tesla, F in newton, m in kg, r in metre.
Use this when the magnetic field is uniform and motion is perpendicular to B for circular motion.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
A proton of mass 1.67 × 10−27 kg and charge 1.6 × 10−19 C enters a 0.20 T magnetic field with speed 2.0 × 106 m s−1 perpendicular to the field.
- 1r = mv/(qB) = (1.67 × 10−27 × 2.0 × 106)/(1.6 × 10−19 × 0.20) = 0.104 m approximately.
- 2The proton follows a circle of radius about 10.4 cm.
Method you can reuse
- 1Identify q, m, v, B, and angle θ.
- 2Choose F = qvB sin θ for magnetic force.
- 3For circular motion with perpendicular entry, equate qvB to mv2/r.
- 4Substitute SI units.
- 5Decide force direction using v × B and reverse it for a negative charge.
Sketch it in your answer
Draw v tangent to the circular path, B perpendicular to the plane, and F toward the centre. Use dot for field out of page and cross for field into page. Label charge sign because force direction reverses for negative charge.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
Why does a charged particle moving perpendicular to a uniform magnetic field move in a circular path?
Think first, then show answerHide answer
Common wrong answer
Using r = qB/(mv) reverses the formula and gives a physically wrong result, where faster particles would have smaller radius.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
Lorentz force is the total force on a charge q moving with velocity v in the presence of electric field E and magnetic field B, given by F = q(E + v × B).
- 2
Add for 2 marks
Example: An electron entering a uniform magnetic field at right angles follows a circular path. The magnetic force changes the direction of velocity but not the speed because it is always perpendicular to the motion.
- 3
Add for 3 marks
The electric part qE acts whether the charge is moving or at rest.
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