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Composition and Size of Nucleus

The nucleus is the small, dense, positively charged central part of an atom containing Z protons and N neutrons. The mass number is A = Z + N, and the nuclear radius is approximately R = R0 A^(1/3), where R0 is about 1.2 fm.

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Student-friendly explanation

Protons determine the atomic number Z and hence the element. Neutrons add to the nuclear mass and influence stability without changing the element. Protons and neutrons together are called nucleons. Since R is proportional to A^(1/3), nuclear volume is proportional to A, so nuclear density is nearly constant for most nuclei. This is a key difference from ordinary matter, where size and density vary strongly with composition.

How to write this in exams

  1. 1

    Start with the exact idea

    The nucleus is the small, dense, positively charged central part of an atom containing Z protons and N neutrons. The mass number is A = Z + N, and the nuclear radius is approximately R = R0 A^(1/3), where R0 is about 1.2 fm.

  2. 2

    Then show how to use it

    Identify Z and A from the given nuclide. Find N using N = A - Z. For radius, write R = R0 A^(1/3). For ratios, cancel R0 and take the cube root of the mass-number ratio. State the answer with correct units or ratio.

  3. 3

    Add one concrete example

    For carbon-12, Z = 6 and A = 12, so N = A - Z = 6. Its approximate radius is R = 1.2 x 12^(1/3) fm, which is about 2.7 fm.

  4. 4

    Avoid this incomplete answer

    For radius ratio, a common wrong answer is R2/R1 = A2/A1. The correct relation uses the cube root, so R2/R1 = (A2/A1)^(1/3).

Definition

The nucleus is the small, dense, positively charged central part of an atom containing Z protons and N neutrons. The mass number is A = Z + N, and the nuclear radius is approximately R = R0 A^(1/3), where R0 is about 1.2 fm.

Example

For carbon-12, Z = 6 and A = 12, so N = A - Z = 6. Its approximate radius is R = 1.2 x 12^(1/3) fm, which is about 2.7 fm.

Rule to remember

A = Z + N, where A is mass number, Z is number of protons, and N is number of neutrons. R = R0 A^(1/3), where R is nuclear radius in metre, R0 is about 1.2 x 10^-15 m, and A is mass number. Use this formula for approximate nuclear size, especially when comparing radii of two nuclei.

Memory hook

A counts all nucleons: protons plus neutrons. Radius grows with the cube root, so eight times the mass number gives only twice the radius.

Examples and method

Worked example

Compare the radii of oxygen-16 and lead-128. Since R is proportional to A^(1/3), R_lead/R_oxygen = (128/16)^(1/3) = 8^(1/3) = 2. The lead-128 nucleus has twice the radius of the oxygen-16 nucleus.

Method to apply

Identify Z and A from the given nuclide. Find N using N = A - Z. For radius, write R = R0 A^(1/3). For ratios, cancel R0 and take the cube root of the mass-number ratio. State the answer with correct units or ratio.

Diagram support

A simple labelled nucleus sketch may show protons and neutrons packed in a small central region with electrons outside the nucleus only for atomic context. Important labels: proton, neutron, nucleon, nucleus, atomic scale versus nuclear scale.

How CBSE asks it

This concept appears as isotope notation questions, radius ratio numericals, neutron-number calculations, and reasoning questions on why nuclear density is nearly constant.

Avoid common mistakes

Common confusion

Students often treat atomic radius and nuclear radius as similar quantities. Nuclear radius is about 10^-15 m in scale, much smaller than atomic radius, which is about 10^-10 m.

Common wrong answer

For radius ratio, a common wrong answer is R2/R1 = A2/A1. The correct relation uses the cube root, so R2/R1 = (A2/A1)^(1/3).

Exam tip

When a question gives isotope notation, first identify A and Z, then calculate N = A - Z. For radius questions, compare using R proportional to A^(1/3), not directly proportional to A.

Quick check

If a nucleus has atomic number 17 and mass number 35, how many neutrons does it contain?

It contains 18 neutrons because the number of neutrons is N = A - Z = 35 - 17 = 18.

Answer writing and exam use

1-mark answer

The nucleus is the small, dense, positively charged central part of an atom containing Z protons and N neutrons. The mass number is A = Z + N, and the nuclear radius is approximately R = R0 A^(1/3), where R0 is about 1.2 fm.

2-mark answer

The nucleus is the small, dense, positively charged central part of an atom containing Z protons and N neutrons. The mass number is A = Z + N, and the nuclear radius is approximately R = R0 A^(1/3), where R0 is about 1.2 fm. A = Z + N, where A is mass number, Z is number of protons, and N is number of neutrons. R = R0 A^(1/3), where R is nuclear radius in metre, R0 is about 1.2 x 10^-15 m, and A is mass number. Use this formula for approximate nuclear size, especially when comparing radii of two nuclei. For carbon-12, Z = 6 and A = 12, so N = A - Z = 6. Its approximate radius is R = 1.2 x 12^(1/3) fm, which is about 2.7 fm.

3-mark answer

Protons determine the atomic number Z and hence the element. Neutrons add to the nuclear mass and influence stability without changing the element. Protons and neutrons together are called nucleons. Since R is proportional to A^(1/3), nuclear volume is proportional to A, so nuclear density is nearly constant for most nuclei. This is a key difference from ordinary matter, where size and density vary strongly with composition. A = Z + N, where A is mass number, Z is number of protons, and N is number of neutrons. R = R0 A^(1/3), where R is nuclear radius in metre, R0 is about 1.2 x 10^-15 m, and A is mass number. Use this formula for approximate nuclear size, especially when comparing radii of two nuclei. Compare the radii of oxygen-16 and lead-128. Since R is proportional to A^(1/3), R_lead/R_oxygen = (128/16)^(1/3) = 8^(1/3) = 2. The lead-128 nucleus has twice the radius of the oxygen-16 nucleus. This concept appears as isotope notation questions, radius ratio numericals, neutron-number calculations, and reasoning questions on why nuclear density is nearly constant. For radius ratio, a common wrong answer is R2/R1 = A2/A1. The correct relation uses the cube root, so R2/R1 = (A2/A1)^(1/3).
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