Three Points Determine a Circle
One and only one circle can pass through three non-collinear points. Its centre is found at the intersection of perpendicular bisectors of two joining segments.
In one line: Three non-straight points fix one circle.
Practice This ConceptUnderstand it
Three points that do not lie on one straight line form a triangle. The perpendicular bisectors of its sides meet at one point, which is equidistant from all three points. That point becomes the centre of the required circle.
Example
Formula and rule
Unique circle condition: three points must be non-collinear.
Centre: intersection of perpendicular bisectors of two sides.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
Given three non-collinear points P, Q, R.
- 1Construct perpendicular bisectors of PQ and QR.
- 2Their intersection O gives OP = OQ = OR, so draw the circle with centre O and radius OP.
Method you can reuse
- 1Join the three points to form two segments.
- 2Construct perpendicular bisectors of two segments.
- 3Mark their intersection as centre.
- 4Draw circle using distance from centre to any one point.
Sketch it in your answer
Draw triangle ABC, perpendicular bisectors of AB and BC meeting at O, then draw circle through A, B and C.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
Why can three collinear points not determine a circle?
Think first, then show answerHide answer
Common wrong answer
Choosing the midpoint of only one side as centre.
Why it loses marks: It may be equidistant from two points, not necessarily from the third.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
One and only one circle can pass through three non-collinear points. Its centre is found at the intersection of perpendicular bisectors of two joining segments.
- 2
Add for 2 marks
Example: For non-collinear points A, B and C, draw perpendicular bisectors of AB and BC. If they meet at O, then OA = OB = OC, so a circle with centre O passes through A, B and C.
- 3
Add for 3 marks
Three points that do not lie on one straight line form a triangle.
Practice this concept with focused MCQs
Open the concept quiz intro first, review the test details, and then start a focused MCQ set from this concept only. Instant score and answer review are live now.
Help improve this page
Found something confusing, incorrect, or missing?