Verifying right triangle using distance
A triangle is right-angled if its side lengths satisfy the Pythagorean relation with the longest side.
In one line: Longest side first, then Pythagoras.
Practice This ConceptUnderstand it
In coordinate geometry, first calculate all three sides using the distance formula. Then identify the longest side and check whether its square equals the sum of the squares of the other two sides. This is the cleanest way to verify a right triangle from coordinates.
Example
Formula and rule
If the longest side is c and the other sides are a and b, then a2 + b2 = c2 for a right triangle.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
- 1For (0, 0), (3, 0), and (3, 4), the side lengths are 3, 4, and 5.
- 2Since 32 + 42 = 52, the triangle is right-angled.
Method you can reuse
- 1Find all three side lengths.
- 2Choose the longest side.
- 3Square all three lengths.
- 4Check whether the sum of the smaller squares equals the square of the longest side.
- 5State the conclusion clearly.
Sketch it in your answer
Plot the three points and mark the longest side mentally or on paper before comparing squares of lengths.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
What should be checked first when verifying a right triangle from coordinates?
Think first, then show answerHide answer
Common wrong answer
A common wrong answer is picking the smallest side as the hypotenuse or checking the wrong pair of sides.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
A triangle is right-angled if its side lengths satisfy the Pythagorean relation with the longest side.
- 2
Add for 2 marks
Example: For points (0, 0), (3, 0), and (3, 4), the side lengths are 3, 4, and 5, so 32 + 42 = 52.
- 3
Add for 3 marks
In coordinate geometry, first calculate all three sides using the distance formula.
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