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Continuity and Differentiability

This chapter connects limits with the behaviour of functions near a point and then builds the derivative as a precise rate of change. Continuity checks whether the function value agrees with the limiting value, while differentiability checks whether the left-hand and right-hand slopes agree. A major exam skill in this chapter is knowing which rule applies under which condition. For example, differentiability implies continuity, but continuity alone does not imply differentiability. Similarly, chain rule, implicit differentiation, logarithmic differentiation, and parametric differentiation each have a specific structure to identify before starting calculation. The chapter is formula-rich, but marks are usually lost in conditions and algebra. You must state one-sided limits, left and right derivatives, domains of inverse trigonometric and logarithmic functions, and non-zero denominator conditions wherever needed. Most long-answer questions combine two or more methods, such as continuity with differentiability, chain rule with inverse trigonometric functions, or logarithmic differentiation with product and quotient forms.

Difficulty

Medium

Study time

70-90 min

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Chapter Learning Map

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Key Concepts

Work through the concepts in order. Each one has an explanation, a worked example, a self-check and an exam answer.

All Concepts

All 7 concepts of the chapter, in the order the NCERT chapter teaches them.

7 concepts
medium difficulty

Continuity at a Point

A function f is continuous at x = a if f(a) is defined, lim(x → a) f(x) exists, and lim(x → a) f(x) = f(a).

9 minOpen concept
medium difficulty

Differentiability and Continuity

A function f is differentiable at x = a if its left-hand derivative and right-hand derivative at a both exist and are equal.

8 minOpen concept
medium difficulty

Chain Rule for Composite Functions

The chain rule gives the derivative of a composite function f(g(x)) by differentiating the outer function at g(x) and multiplying by the derivative of g(x).

7 minOpen concept
medium difficulty

Implicit Differentiation

Implicit differentiation is used when x and y are related by an equation and y is not first written explicitly as a function of x.

7 minOpen concept
medium difficulty

Derivatives of Inverse Trigonometric, Exponential, and Logarithmic Functions

This concept covers standard derivatives of inverse trigonometric functions, exponential functions, and logarithmic functions, along with their domain conditions.

7 minOpen concept
medium difficulty

Logarithmic Differentiation

Logarithmic differentiation is a method where logarithms are taken on both sides before differentiating, especially for variable powers and complicated products or quotients.

8 minOpen concept
medium difficulty

Parametric and Second-Order Derivatives

For parametric equations x = f(t), y = g(t), the derivative dy/dx is found as (dy/dt)/(dx/dt), provided dx/dt is not zero. The second-order derivative measures the rate of change of dy/dx with respect to x.

7 minOpen concept

Exam Intelligence

The traps that cost marks in this chapter, and how its main concepts turn up in the paper.

Common Traps

  • Assuming continuity proves differentiability.
  • Using the wrong branch to calculate f(a) in a piecewise function.
  • Forgetting the inner derivative in chain rule.
  • Differentiating yn as nyn−1 instead of nyn−1dy/dx during implicit differentiation.
  • Missing the negative sign in the derivative of cos−1 x.
  • Forgetting to multiply by y at the end of logarithmic differentiation.
  • Calling d/dt(dy/dx) the second derivative without dividing by dx/dt.

How CBSE Asks This Chapter

  • Continuity at a Point

    Usually asked by giving a piecewise function and asking for unknown constants that make it continuous at one or two points.

  • Differentiability and Continuity

    Often asked as a parameter-finding problem where a piecewise function must be continuous and differentiable at the joining point.

  • Chain Rule for Composite Functions

    Appears as direct differentiation, part of implicit differentiation, or combined with inverse trigonometric, logarithmic, and exponential functions.

  • Implicit Differentiation

    Questions give equations such as x2 + y2 = a2, xy = c, or expressions with powers and products, then ask for dy/dx.

Quick Revision

Concept, formula or equation to remember, and the trap that loses marks — in one scannable view.

  • Continuity at a Point

    Remember

    Continuity at x = a: LHL = RHL = f(a).

    Trap to avoid

    Students often equate only the two formula pieces and forget to compare them with f(a), especially when the equality sign belongs to one side of a piecewise function.

  • Differentiability and Continuity

    Remember

    LHD = lim(h → 0-) [f(a + h) - f(a)]/h and RHD = lim(h → 0+) [f(a + h) - f(a)]/h.

    Trap to avoid

    A frequent wrong claim is that continuity automatically proves differentiability.

  • Chain Rule for Composite Functions

    Remember

    If y = f(g(x)), then dy/dx = f'(g(x))g'(x).

    Trap to avoid

    Students differentiate the outer function correctly but forget to multiply by the derivative of the inner function.

  • Implicit Differentiation

    Remember

    Key condition: y is treated as a differentiable function of x.

    Trap to avoid

    Students differentiate y2 as 2y instead of 2y dy/dx, which ignores that y depends on x.

  • Derivatives of Inverse Trigonometric, Exponential, and Logarithmic Functions

    Remember

    d/dx(sin−1 x) = 1/√(1 - x2), d/dx(cos−1 x) = -1/√(1 - x2), d/dx(tan−1 x) = 1/(1 + x2), d/dx(ex) = ex, d/dx(ax) = ax log a, d/dx(log x) = 1/x for x > 0.

    Trap to avoid

    Students often write the correct outer derivative but ignore the derivative of the inside expression, especially in sin−1(2x) or log(3x + 1).

  • Logarithmic Differentiation

    Remember

    If y = u(x)v(x) with u(x) > 0, then log y = v(x)log u(x), and dy/dx = y[v'(x)log u(x) + v(x)u'(x)/u(x)].

    Trap to avoid

    Students take logarithms but forget to multiply the final derivative expression by y when converting from (1/y)dy/dx to dy/dx.

  • Parametric and Second-Order Derivatives

    Remember

    For x = f(t), y = g(t): dy/dx = (dy/dt)/(dx/dt), where dx/dt ≠ 0.

    Trap to avoid

    Students calculate d/dt(dy/dx) and call it d2y/dx2 without dividing by dx/dt.

Practice

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