Consistency of Linear Equations
A system of linear equations is consistent if it has at least one solution. It is inconsistent if it has no solution.
In one line: Non-zero determinant gives one answer; zero determinant needs a consistency test.
Practice This ConceptUnderstand it
For AX = B, determinant methods help test solution type. If |A| ≠ 0, the system has a unique solution. If |A| = 0, use adj(A)B to distinguish cases: when adj(A)B is a non-zero matrix, the system is inconsistent; when adj(A)B is a zero matrix, the system may have infinitely many solutions or needs further examination depending on the equations.
Example
Formula and rule
For AX = B: if |A| ≠ 0, unique solution.
If |A| = 0 and adj(A)B is non-zero, no solution.
If |A| = 0 and adj(A)B is zero, the system is consistent with infinitely many solutions or requires further equation-level verification.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
Test consistency of x + y = 3 and 2x + 2y = 6.
- 1A = [[1,1],[2,2]], B = [[3],[6]]. |A| = 1×2 - 1×2 = 0.
- 2The second equation is exactly twice the first, including the constant.
- 3Therefore the equations represent the same line and have infinitely many solutions; the system is consistent.
Method you can reuse
- 1Write the system as AX = B.
- 2Compute |A|.
- 3If |A| ≠ 0, state unique solution.
- 4If |A| = 0, compare dependence of equations or compute adj(A)B.
- 5Then classify as inconsistent, infinitely many solutions, or needing further verification.
Visual tip
No diagram is required. For two-variable systems, line graphs can optionally show intersecting, parallel, or coincident lines.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
If |A| ≠ 0 for AX = B, what type of solution does the system have?
Think first, then show answerHide answer
Common wrong answer
Saying the inverse exists when |A| = 0 and trying to solve by X = A−1B.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
A system of linear equations is consistent if it has at least one solution. It is inconsistent if it has no solution.
- 2
Add for 2 marks
Example: For equations x + y = 2 and 2x + 2y = 5, A = [[1,1],[2,2]], so |A| = 0. The left sides are proportional, but constants are not proportional; hence the system has no solution.
- 3
Add for 3 marks
For AX = B, determinant methods help test solution type.
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