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Consistency of Linear Equations

A system of linear equations is consistent if it has at least one solution. It is inconsistent if it has no solution.

In one line: Non-zero determinant gives one answer; zero determinant needs a consistency test.

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Understand it

For AX = B, determinant methods help test solution type. If |A| ≠ 0, the system has a unique solution. If |A| = 0, use adj(A)B to distinguish cases: when adj(A)B is a non-zero matrix, the system is inconsistent; when adj(A)B is a zero matrix, the system may have infinitely many solutions or needs further examination depending on the equations.

Example

For equations x + y = 2 and 2x + 2y = 5, A = [[1,1],[2,2]], so |A| = 0. The left sides are proportional, but constants are not proportional; hence the system has no solution.

Formula and rule

For AX = B: if |A| ≠ 0, unique solution.

If |A| = 0 and adj(A)B is non-zero, no solution.

If |A| = 0 and adj(A)B is zero, the system is consistent with infinitely many solutions or requires further equation-level verification.

See it worked out

Follow the example line by line, then use the same method on new questions.

Worked example

Test consistency of x + y = 3 and 2x + 2y = 6.

  1. 1A = [[1,1],[2,2]], B = [[3],[6]]. |A| = 1×2 - 1×2 = 0.
  2. 2The second equation is exactly twice the first, including the constant.
  3. 3Therefore the equations represent the same line and have infinitely many solutions; the system is consistent.

Method you can reuse

  1. 1Write the system as AX = B.
  2. 2Compute |A|.
  3. 3If |A| ≠ 0, state unique solution.
  4. 4If |A| = 0, compare dependence of equations or compute adj(A)B.
  5. 5Then classify as inconsistent, infinitely many solutions, or needing further verification.

Visual tip

No diagram is required. For two-variable systems, line graphs can optionally show intersecting, parallel, or coincident lines.

Check yourself

Answer the question in your head before opening the answer.

Try it yourself

If |A| ≠ 0 for AX = B, what type of solution does the system have?

Think first, then show answer
It has a unique solution.

Common wrong answer

Saying the inverse exists when |A| = 0 and trying to solve by X = A−1B.

Don't mix this up

Assuming |A| = 0 always means infinitely many solutions. It may also mean no solution.

Exam tip

When |A| = 0, compare both coefficients and constants or use adj(A)B; do not declare the result from determinant alone.

Write it in the exam

Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.

How CBSE asks it

Students may be asked to check consistency, find values of a parameter for which a system has unique or non-unique solutions, or classify solution type.
  1. 1

    Enough for 1 mark

    A system of linear equations is consistent if it has at least one solution. It is inconsistent if it has no solution.

  2. 2

    Add for 2 marks

    Example: For equations x + y = 2 and 2x + 2y = 5, A = [[1,1],[2,2]], so |A| = 0. The left sides are proportional, but constants are not proportional; hence the system has no solution.

  3. 3

    Add for 3 marks

    For AX = B, determinant methods help test solution type.

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