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Determinant of a Matrix

The determinant of a square matrix is a scalar value denoted by |A| or det(A). It is defined for square matrices only and can be evaluated by direct formula for order 1 and 2, and by expansion along any row or column for order 3.

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Student-friendly explanation

For a 1 by 1 matrix [a], the determinant is a. For a 2 by 2 matrix, multiply the main diagonal entries and subtract the product of the other diagonal entries. For a 3 by 3 matrix, choose a row or column, multiply each entry by its cofactor, and add the signed terms. The value remains the same whichever row or column is chosen, though some choices make calculation shorter.

How to write this in exams

  1. 1

    Start with the exact idea

    The determinant of a square matrix is a scalar value denoted by |A| or det(A). It is defined for square matrices only and can be evaluated by direct formula for order 1 and 2, and by expansion along any row or column for order 3.

  2. 2

    Then show how to use it

    Check that the matrix is square. For order 2, apply ad - bc. For order 3, choose a convenient row or column. Write each cofactor with its sign. Simplify carefully and state the determinant value.

  3. 3

    Add one concrete example

    For A = [[2,3],[5,7]], |A| = 2(7) - 3(5) = 14 - 15 = -1.

  4. 4

    Avoid this incomplete answer

    Writing ad + bc instead of ad - bc for a 2 by 2 determinant.

Definition

The determinant of a square matrix is a scalar value denoted by |A| or det(A). It is defined for square matrices only and can be evaluated by direct formula for order 1 and 2, and by expansion along any row or column for order 3.

Example

For A = [[2,3],[5,7]], |A| = 2(7) - 3(5) = 14 - 15 = -1.

Rule to remember

For [[a,b],[c,d]], determinant = ad - bc. For a 3 by 3 determinant, |A| = a11A11 + a12A12 + a13A13 when expanding along the first row, where Aij is the cofactor of aij.

Memory hook

For 2 by 2 determinants: down product minus up product.

Examples and method

Worked example

Evaluate |A| for A = [[1,2,3],[0,4,5],[0,0,6]]. Expanding along the first column: |A| = 1×|[[4,5],[0,6]]| - 0 + 0 = 1(4×6 - 5×0) = 24. Therefore, det(A) = 24.

Method to apply

Check that the matrix is square. For order 2, apply ad - bc. For order 3, choose a convenient row or column. Write each cofactor with its sign. Simplify carefully and state the determinant value.

Diagram support

No diagram is required because the concept is algebraic. A boxed 2 by 2 or 3 by 3 determinant layout can help students track diagonal products and cofactors.

How CBSE asks it

Students may be asked to evaluate a determinant directly, simplify a determinant containing variables, or identify whether a determinant is zero.

Avoid common mistakes

Common confusion

Using determinant notation for a non-square matrix. A determinant is not defined for a rectangular matrix.

Common wrong answer

Writing ad + bc instead of ad - bc for a 2 by 2 determinant.

Exam tip

For a 3 by 3 determinant, expand along the row or column containing the most zeros or simplest numbers.

Quick check

Find the determinant of [[4, -1], [2, 3]].

|A| = 4(3) - (-1)(2) = 12 + 2 = 14.

Answer writing and exam use

1-mark answer

The determinant of a square matrix is a scalar value denoted by |A| or det(A). It is defined for square matrices only and can be evaluated by direct formula for order 1 and 2, and by expansion along any row or column for order 3.

2-mark answer

The determinant of a square matrix is a scalar value denoted by |A| or det(A). It is defined for square matrices only and can be evaluated by direct formula for order 1 and 2, and by expansion along any row or column for order 3. For [[a,b],[c,d]], determinant = ad - bc. For a 3 by 3 determinant, |A| = a11A11 + a12A12 + a13A13 when expanding along the first row, where Aij is the cofactor of aij. For A = [[2,3],[5,7]], |A| = 2(7) - 3(5) = 14 - 15 = -1.

3-mark answer

For a 1 by 1 matrix [a], the determinant is a. For a 2 by 2 matrix, multiply the main diagonal entries and subtract the product of the other diagonal entries. For a 3 by 3 matrix, choose a row or column, multiply each entry by its cofactor, and add the signed terms. The value remains the same whichever row or column is chosen, though some choices make calculation shorter. For [[a,b],[c,d]], determinant = ad - bc. For a 3 by 3 determinant, |A| = a11A11 + a12A12 + a13A13 when expanding along the first row, where Aij is the cofactor of aij. Evaluate |A| for A = [[1,2,3],[0,4,5],[0,0,6]]. Expanding along the first column: |A| = 1×|[[4,5],[0,6]]| - 0 + 0 = 1(4×6 - 5×0) = 24. Therefore, det(A) = 24. Students may be asked to evaluate a determinant directly, simplify a determinant containing variables, or identify whether a determinant is zero. Writing ad + bc instead of ad - bc for a 2 by 2 determinant.
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