Resonance in a Series LCR Circuit
Resonance in a series LCR circuit occurs when inductive reactance equals capacitive reactance, making impedance minimum and current maximum.
In one line: At resonance, L and C cancel their reactance, leaving only R to control current.
Concept Practice Coming SoonUnderstand it
- At resonance, XL = XC.
- Therefore the net reactance XL - XC becomes zero and the circuit behaves like a pure resistor.
- The impedance becomes Z = R, which is its minimum value, so current reaches its maximum value Imax = Vrms/R.
- The resonant angular frequency is ω0 = 1/√LC.
- A sharp resonance means current changes greatly for a small change in frequency, and this sharpness is measured using the quality factor Q.
Example
Formula and rule
Condition: XL = XC.
Since ω L = 1/(ω C), ω0 = 1/√LC.
Resonant frequency f0 = 1/(2 π √LC).
At resonance, Z = R, phi = 0, and power factor = 1.
Q-factor for a series circuit may be written as Q = ω0 L/R = 1/(ω0 C R).
L is in henry, C in farad, R in ohm, ω0 in rad s−1, and f0 in hertz.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
- 1A series LCR circuit has L = 0.5 H and C = 8 microfarad. ω0 = 1/√LC = 1/√(0.5 × 8 × 10−6) = 1/√(4 × 10−6) = 1/(2 × 10−3) = 500 rad s−1.
- 2If R = 50 ohm and Vrms = 100 V, current at resonance is I = V/R = 100/50 = 2 A.
Method you can reuse
- 1Set XL = XC.
- 2Substitute ω L = 1/(ω C).
- 3Solve for ω0.
- 4Convert to f0 if required.
- 5At resonance, take Z = R and calculate current using RMS voltage.
- 6Add the physical meaning: current maximum and circuit purely resistive.
Visual tip
A resonance curve of current versus frequency is useful. The x-axis is frequency, the y-axis is current, and the peak occurs at f0. A sharper peak represents larger Q. If a phasor is drawn at resonance, VL and VC are equal and opposite.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
Why is current maximum at resonance in a series LCR circuit?
Think first, then show answerHide answer
Common wrong answer
Using ω0 = √LC.
Why it loses marks: The correct relation is the reciprocal square root, ω0 = 1/√LC.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
Resonance in a series LCR circuit occurs when inductive reactance equals capacitive reactance, making impedance minimum and current maximum.
- 2
Add for 2 marks
Example: Radio tuning uses resonance. A receiver selects a particular frequency when its LC circuit resonates with the frequency of the desired signal.
- 3
Add for 3 marks
Therefore the net reactance XL - XC becomes zero and the circuit behaves like a pure resistor.
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