Series LCR Circuit: Impedance and Phasor Relation
A series LCR circuit contains a resistor, inductor, and capacitor in series with an AC source; its total opposition to current is impedance Z = sqrt(R^2 + (XL - XC)^2).
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Student-friendly explanation
In a series LCR circuit, the same current flows through R, L, and C. The resistor voltage VR is in phase with current, the inductor voltage VL leads current by pi/2, and the capacitor voltage VC lags current by pi/2. Since VL and VC are in opposite directions in the phasor diagram, the effective reactive voltage is VL - VC. The applied voltage is the vector sum of VR and the net reactive voltage, giving V = sqrt(VR^2 + (VL - VC)^2). Dividing by current gives Z = sqrt(R^2 + (XL - XC)^2). The phase angle is tan phi = (XL - XC)/R.
How to write this in exams
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Start with the exact idea
A series LCR circuit contains a resistor, inductor, and capacitor in series with an AC source; its total opposition to current is impedance Z = sqrt(R^2 + (XL - XC)^2).
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Then show how to use it
Calculate XL and XC if needed. Find net reactance XL - XC with sign. Compute Z using the square-root formula. Use I = V/Z. Decide the circuit nature from the sign of XL - XC. Draw phasors using current as the reference.
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Add one concrete example
If XL is greater than XC, the circuit behaves inductively and current lags the applied voltage. If XC is greater than XL, the circuit behaves capacitively and current leads the applied voltage.
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Avoid this incomplete answer
Adding all three as Z = R + XL + XC gives a larger and physically wrong impedance because it ignores phase.
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Why is impedance in a series LCR circuit not simply R + XL + XC?
Impedance is not R + XL + XC because resistance, inductive reactance, and capacitive reactance do not act in the same phase direction. The reactive parts oppose each other, so the net reactance is XL - XC and Z = sqrt(R^2 + (XL - XC)^2).
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