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Bohr Model of the Hydrogen Atom

Bohr's model of hydrogen states that the electron can revolve only in certain stable stationary orbits without radiating energy, and radiation is emitted or absorbed only when the electron jumps between allowed energy levels.

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Student-friendly explanation

Bohr modified the Rutherford model by adding quantum conditions. The electron is allowed only in orbits where its angular momentum is an integral multiple of h divided by 2π. While in such an orbit, it does not radiate energy. When it moves from a higher energy level to a lower energy level, it emits a photon; when it absorbs the right energy, it moves to a higher level. The model works best for hydrogen and hydrogen-like single-electron species.

How to write this in exams

  1. 1

    Start with the exact idea

    Bohr's model of hydrogen states that the electron can revolve only in certain stable stationary orbits without radiating energy, and radiation is emitted or absorbed only when the electron jumps between allowed energy levels.

  2. 2

    Then show how to use it

    Step 1: Write the relevant Bohr postulate. Step 2: Identify n, initial level, and final level. Step 3: Apply L = nh/2π for orbit questions or = energy difference for transition questions. Step 4: Keep units consistent. Step 5: Interpret whether the transition is emission or absorption.

  3. 3

    Add one concrete example

    For hydrogen, the first orbit has n = 1 and the second orbit has n = 2. A transition from n = 3 to n = 2 gives a photon in the Balmer series because the final level is n = 2.

  4. 4

    Avoid this incomplete answer

    A common wrong answer is taking the numerical energy difference as negative for emitted photon energy. Photon energy must be reported as a positive amount; the atom's energy decreases during emission.

Definition

Bohr's model of hydrogen states that the electron can revolve only in certain stable stationary orbits without radiating energy, and radiation is emitted or absorbed only when the electron jumps between allowed energy levels.

Example

For hydrogen, the first orbit has n = 1 and the second orbit has n = 2. A transition from n = 3 to n = 2 gives a photon in the Balmer series because the final level is n = 2.

Rule to remember

Angular momentum quantisation: L = mvr = nh/2π, where m is electron mass in kg, v is orbital speed in m s^-1, r is orbit radius in m, n is the principal quantum number, and h is Planck's constant in J s. Transition rule: = Ei - Ef for emission, where ν is frequency in Hz and energies are in joule or consistently in eV. Use for hydrogen or hydrogen-like one-electron systems.

Memory hook

Bohr orbits are allowed parking levels; light appears only when the electron changes level.

Examples and method

Worked example

An electron in hydrogen jumps from n = 3 to n = 2. Using En = -13.6/n^2 eV, E3 = -13.6/9 = -1.51 eV and E2 = -13.6/4 = -3.40 eV. Photon energy for emission = E3 - E2 = (-1.51) - (-3.40) = 1.89 eV. Interpretation: the atom emits a photon of energy 1.89 eV in the Balmer series.

Method to apply

Step 1: Write the relevant Bohr postulate. Step 2: Identify n, initial level, and final level. Step 3: Apply L = nh/2π for orbit questions or = energy difference for transition questions. Step 4: Keep units consistent. Step 5: Interpret whether the transition is emission or absorption.

Diagram support

Draw a central nucleus with circular allowed orbits labelled n = 1, n = 2, n = 3. Show an inward arrow for emission and an outward arrow for absorption. Label photon for the transition.

How CBSE asks it

Questions may ask for Bohr's postulates, the meaning of stationary orbit, angular momentum quantisation, photon energy in a transition, or why Bohr's model improves Rutherford's model.

Avoid common mistakes

Common confusion

Students often use = Ef - Ei for emission without checking signs. For emission from higher to lower level, photon energy is Ei - Ef, a positive value.

Common wrong answer

A common wrong answer is taking the numerical energy difference as negative for emitted photon energy. Photon energy must be reported as a positive amount; the atom's energy decreases during emission.

Exam tip

Always identify initial and final levels first. For emission, higher n to lower n; for absorption, lower n to higher n.

Quick check

What are the two main quantum ideas in Bohr's model of hydrogen?

Bohr's model says that only certain stationary orbits are allowed, with angular momentum L = nh/2π, and that light is emitted or absorbed only when the electron jumps between these allowed energy levels with photon energy equal to the energy difference.

Answer writing and exam use

1-mark answer

Bohr's model of hydrogen states that the electron can revolve only in certain stable stationary orbits without radiating energy, and radiation is emitted or absorbed only when the electron jumps between allowed energy levels.

2-mark answer

Bohr's model of hydrogen states that the electron can revolve only in certain stable stationary orbits without radiating energy, and radiation is emitted or absorbed only when the electron jumps between allowed energy levels. Angular momentum quantisation: L = mvr = nh/2π, where m is electron mass in kg, v is orbital speed in m s^-1, r is orbit radius in m, n is the principal quantum number, and h is Planck's constant in J s. Transition rule: = Ei - Ef for emission, where ν is frequency in Hz and energies are in joule or consistently in eV. Use for hydrogen or hydrogen-like one-electron systems. For hydrogen, the first orbit has n = 1 and the second orbit has n = 2. A transition from n = 3 to n = 2 gives a photon in the Balmer series because the final level is n = 2.

3-mark answer

Bohr modified the Rutherford model by adding quantum conditions. The electron is allowed only in orbits where its angular momentum is an integral multiple of h divided by 2π. While in such an orbit, it does not radiate energy. When it moves from a higher energy level to a lower energy level, it emits a photon; when it absorbs the right energy, it moves to a higher level. The model works best for hydrogen and hydrogen-like single-electron species. Angular momentum quantisation: L = mvr = nh/2π, where m is electron mass in kg, v is orbital speed in m s^-1, r is orbit radius in m, n is the principal quantum number, and h is Planck's constant in J s. Transition rule: = Ei - Ef for emission, where ν is frequency in Hz and energies are in joule or consistently in eV. Use for hydrogen or hydrogen-like one-electron systems. An electron in hydrogen jumps from n = 3 to n = 2. Using En = -13.6/n^2 eV, E3 = -13.6/9 = -1.51 eV and E2 = -13.6/4 = -3.40 eV. Photon energy for emission = E3 - E2 = (-1.51) - (-3.40) = 1.89 eV. Interpretation: the atom emits a photon of energy 1.89 eV in the Balmer series. Questions may ask for Bohr's postulates, the meaning of stationary orbit, angular momentum quantisation, photon energy in a transition, or why Bohr's model improves Rutherford's model. A common wrong answer is taking the numerical energy difference as negative for emitted photon energy. Photon energy must be reported as a positive amount; the atom's energy decreases during emission.
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