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Checking remainder through factor

If a polynomial p(x) is divided by x-a, then the remainder is p(a). If p(a)=0, then x-a is a factor of the polynomial.

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Student-friendly explanation

This is one of the fastest checks in the chapter. Instead of doing full division every time, we can substitute a into the polynomial. If the result is zero, then x-a is a factor. If the result is not zero, that number is the remainder. This idea links factor theorem and remainder theorem closely.

How to write this in exams

  1. 1

    Start with the exact idea

    If a polynomial p(x) is divided by x-a, then the remainder is p(a). If p(a)=0, then x-a is a factor of the polynomial.

  2. 2

    Then show how to use it

    1. Match the divisor x-a with the test value a. 2. Substitute a into the polynomial. 3. Calculate the value. 4. If the value is 0, the binomial is a factor; otherwise it is the remainder.

  3. 3

    Add one concrete example

    For p(x)=x^2-4x+3, p(1)=0, so x-1 is a factor.

  4. 4

    Avoid this incomplete answer

    A common wrong answer is to test the negative of the number in the divisor. The sign should be read from x-a carefully.

Definition

If a polynomial p(x) is divided by x-a, then the remainder is p(a). If p(a)=0, then x-a is a factor of the polynomial.

Example

For p(x)=x^2-4x+3, p(1)=0, so x-1 is a factor.

Rule to remember

Remainder on division by x-a is p(a). If p(a)=0, then x-a is a factor of p(x).

Memory hook

Factor x-a means test a.

Examples and method

Worked example

For p(x)=x^2-5x+6 and divisor x-2, compute p(2)=4-10+6=0. So x-2 is a factor and the remainder is 0.

Method to apply

1. Match the divisor x-a with the test value a. 2. Substitute a into the polynomial. 3. Calculate the value. 4. If the value is 0, the binomial is a factor; otherwise it is the remainder.

Diagram support

A short division layout can be paired with a substitution check to show why the remainder is zero.

How CBSE asks it

Check whether a given binomial is a factor, find remainder quickly, or verify a factor without long division.

Avoid common mistakes

Common confusion

Students often reverse the factor sign and test the wrong value. For x-a, the test value is a, not -a.

Common wrong answer

A common wrong answer is to test the negative of the number in the divisor. The sign should be read from x-a carefully.

Exam tip

When the divisor is x-a, substitute a directly into p(x).

Quick check

If a polynomial is divided by x-3, what gives the remainder?

Substitute 3 into the polynomial. The value p(3) is the remainder, and if p(3)=0 then x-3 is a factor.

Answer writing and exam use

1-mark answer

If a polynomial p(x) is divided by x-a, then the remainder is p(a). If p(a)=0, then x-a is a factor of the polynomial.

2-mark answer

If a polynomial p(x) is divided by x-a, then the remainder is p(a). If p(a)=0, then x-a is a factor of the polynomial. Remainder on division by x-a is p(a). If p(a)=0, then x-a is a factor of p(x). For p(x)=x^2-4x+3, p(1)=0, so x-1 is a factor.

3-mark answer

This is one of the fastest checks in the chapter. Instead of doing full division every time, we can substitute a into the polynomial. If the result is zero, then x-a is a factor. If the result is not zero, that number is the remainder. This idea links factor theorem and remainder theorem closely. Remainder on division by x-a is p(a). If p(a)=0, then x-a is a factor of p(x). For p(x)=x^2-5x+6 and divisor x-2, compute p(2)=4-10+6=0. So x-2 is a factor and the remainder is 0. Check whether a given binomial is a factor, find remainder quickly, or verify a factor without long division. A common wrong answer is to test the negative of the number in the divisor. The sign should be read from x-a carefully.
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