Relationship between zeros and coefficients of a cubic polynomial
If α, β, and γ are the zeros of ax^3+bx^2+cx+d, then α+β+γ=-b/a, αβ+βγ+γα=c/a, and αβγ=-d/a.
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Student-friendly explanation
This result extends the quadratic relationship to cubics. It is useful when one or more zeros are known, or when a cubic polynomial is formed from given roots. The signs must be read carefully from the standard form. This relation saves time and is often used in higher-level algebra questions.
How to write this in exams
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Start with the exact idea
If α, β, and γ are the zeros of ax^3+bx^2+cx+d, then α+β+γ=-b/a, αβ+βγ+γα=c/a, and αβγ=-d/a.
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Then show how to use it
1. Compare the polynomial with ax^3+bx^2+cx+d. 2. Note a, b, c, and d with signs. 3. Apply the three formulas carefully. 4. Use them to verify or construct the polynomial.
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Add one concrete example
For x^3-6x^2+11x-6, sum of zeros is 6, sum of pairwise products is 11, and product of zeros is 6.
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Avoid this incomplete answer
A common wrong answer is to write the product as d/a. The negative sign is required because the cubic relation changes sign for the constant term.
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What is the product of zeros of ax^3+bx^2+cx+d?
The product of the zeros is -d/a. The negative sign is important, so students should read the constant term carefully from the standard form.
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