Euclid division lemma
If one integer a is divided by another positive integer b, we can write a = bq + r, where q is the quotient and r is the remainder, with 0 ≤ r < b.
In one line: Remainder stays small: always smaller than the divisor.
Practice This ConceptUnderstand it
This lemma gives the exact form of division with remainder. It tells us that the remainder is not free to take any value; it must stay smaller than the divisor and cannot be negative. That strict form is useful in HCF methods and in proof-based questions.
Example
Formula and rule
a = bq + r, where 0 ≤ r < b.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
Write 157 = 12 × 13 + 1.
- 1Here 157 is the dividend, 12 is the divisor, 13 is the quotient, and 1 is the remainder.
- 2Since 1 is smaller than 12, the form is correct.
Method you can reuse
- 1Divide a by b.
- 2Write a = bq + r.
- 3Check that r is not negative.
- 4Check that r is smaller than b.
- 5If both conditions hold, the form is correct.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
In the division of 157 by 12, what must be true about the remainder?
Think first, then show answerHide answer
Common wrong answer
Writing 157 = 12 × 12 + 13.
Why it loses marks: The remainder 13 is not smaller than the divisor 12.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
If one integer a is divided by another positive integer b, we can write a = bq + r, where q is the quotient and r is the remainder, with 0 ≤ r < b.
- 2
Add for 2 marks
Example: When 157 is divided by 12, we can write 157 = 12 × 13 + 1, so the quotient is 13 and the remainder is 1.
- 3
Add for 3 marks
This lemma gives the exact form of division with remainder.
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