Proof of irrationality of sqrt(2)
Assume √2 = p/q in lowest terms. After squaring, 2q2 = p2, so p is even. That leads to q also being even, which contradicts the fraction being in lowest terms.
In one line: Even numerator leads to even denominator; lowest terms cannot survive.
Practice This ConceptUnderstand it
This is a proof by contradiction. If both p and q become divisible by 2, then the fraction was not in lowest terms after all. That contradiction shows √2 cannot be rational.
Example
Formula and rule
Assume √2 = p/q in lowest terms, then 2q2 = p2.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
Let √2 = p/q in lowest terms.
- 1Then p2 = 2q2, so p is even.
- 2Write p = 2k.
- 3Substituting gives 4k2 = 2q2, so q2 = 2k2 and q is even.
- 4Both being even is impossible in lowest terms.
Method you can reuse
- 1Assume √2 = p/q in lowest terms.
- 2Square both sides.
- 3Show p is even.
- 4Substitute p = 2k.
- 5Show q is even.
- 6Contradict lowest terms.
Visual tip
A proof ladder with the steps assumption, square, evenness, contradiction, and conclusion works well.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
Why does the proof of √2 fail once both p and q are even?
Think first, then show answerHide answer
Common wrong answer
Saying p is even, so √2 is rational,.
Why it loses marks: The same argument forces q to be even too.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
Assume √2 = p/q in lowest terms. After squaring, 2q2 = p2, so p is even. That leads to q also being even, which contradicts the fraction being in lowest terms.
- 2
Add for 2 marks
Example: If p is even, write p = 2k. Then 4k2 = 2q2, so q2 = 2k2 and q is also even.
- 3
Add for 3 marks
This is a proof by contradiction.
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