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Median of grouped data

The median of grouped data is the middle value that divides the frequency distribution into two equal parts.

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Student-friendly explanation

For grouped data, we first find the median class using cumulative frequency. Then we apply the median formula with lower boundary, total frequency, cumulative frequency before the median class, and class width. This gives the central value of the distribution.

How to write this in exams

  1. 1

    Start with the exact idea

    The median of grouped data is the middle value that divides the frequency distribution into two equal parts.

  2. 2

    Then show how to use it

    1. Find total frequency N. 2. Compute N/2. 3. Locate the median class using cumulative frequency. 4. Note l, cf, f, and h. 5. Substitute into the median formula.

  3. 3

    Add one concrete example

    If the total frequency is 50, the median is located around the 25th observation and then calculated using the median class.

  4. 4

    Avoid this incomplete answer

    A common wrong answer is to use the modal class or the largest frequency class instead of the median class.

Definition

The median of grouped data is the middle value that divides the frequency distribution into two equal parts.

Example

If the total frequency is 50, the median is located around the 25th observation and then calculated using the median class.

Rule to remember

Median = l + [(N/2 - cf) / f] x h, where l is lower boundary, cf is cumulative frequency before median class, f is frequency of median class, and h is class width.

Memory hook

Median means the middle position, not the biggest frequency.

Examples and method

Worked example

If N = 40, N/2 = 20. Suppose cumulative frequencies are 5, 13, 22, 30. The median class is the class where cumulative frequency first crosses 20, that is the third class. If l = 20, cf = 13, f = 9, and h = 10, then median = 20 + [(20 - 13)/9] x 10 = 27.78.

Method to apply

1. Find total frequency N. 2. Compute N/2. 3. Locate the median class using cumulative frequency. 4. Note l, cf, f, and h. 5. Substitute into the median formula.

Diagram support

Use a cumulative frequency table to mark N/2 and identify the median class clearly.

How CBSE asks it

Questions usually give grouped data and ask for the median using cumulative frequency and the standard median formula.

Avoid common mistakes

Common confusion

Students often choose the class with the highest frequency instead of the class containing the middle position.

Common wrong answer

A common wrong answer is to use the modal class or the largest frequency class instead of the median class.

Exam tip

Always find N/2 first and then locate the class where the cumulative frequency first becomes greater than or equal to N/2.

Quick check

How do you identify the median class in grouped data?

You identify the median class by finding N/2 and then looking for the first cumulative frequency that is greater than or equal to N/2. That class contains the median.

Answer writing and exam use

1-mark answer

The median of grouped data is the middle value that divides the frequency distribution into two equal parts.

2-mark answer

The median of grouped data is the middle value that divides the frequency distribution into two equal parts. Median = l + [(N/2 - cf) / f] x h, where l is lower boundary, cf is cumulative frequency before median class, f is frequency of median class, and h is class width. If the total frequency is 50, the median is located around the 25th observation and then calculated using the median class.

3-mark answer

For grouped data, we first find the median class using cumulative frequency. Then we apply the median formula with lower boundary, total frequency, cumulative frequency before the median class, and class width. This gives the central value of the distribution. Median = l + [(N/2 - cf) / f] x h, where l is lower boundary, cf is cumulative frequency before median class, f is frequency of median class, and h is class width. If N = 40, N/2 = 20. Suppose cumulative frequencies are 5, 13, 22, 30. The median class is the class where cumulative frequency first crosses 20, that is the third class. If l = 20, cf = 13, f = 9, and h = 10, then median = 20 + [(20 - 13)/9] x 10 = 27.78. Questions usually give grouped data and ask for the median using cumulative frequency and the standard median formula. A common wrong answer is to use the modal class or the largest frequency class instead of the median class.
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