Step deviation method
The step deviation method is a fast way to find the mean of grouped data when class widths are equal.
In one line: Same width, smaller numbers, faster mean.
Practice This ConceptUnderstand it
This method is used when the class intervals have the same width. We choose an assumed mean, divide deviations by class width to get small coded values, and then use a simpler formula. It is especially helpful in long tables because the numbers become easier to manage.
Example
Formula and rule
Mean = A + [Σfi ui / Σfi] x h, where ui = (xi - A)/h and h is class width.
See it worked out
Follow the example line by line, then use the same method on new questions.
Worked example
For class marks 15, 25, 35 with frequencies 2, 3, 5, choose A = 25 and h = 10.
- 1Then ui values are -1, 0, 1.
- 2So Σfi ui = 2(-1) + 3(0) + 5(1) = 3.
- 3Mean = 25 + (3/10)x10 = 28.
Method you can reuse
- 1Check whether class width is common.
- 2Choose an assumed mean.
- 3Compute deviations from it.
- 4Divide by class width to get ui.
- 5Multiply by frequencies and apply the formula.
Sketch it in your answer
Draw a table with columns for class mark, deviation, ui, frequency, and fi ui.
Check yourself
Answer the question in your head before opening the answer.
Try it yourself
When is the step deviation method most suitable?
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Common wrong answer
A common wrong answer is to forget multiplying the coded deviation sum by class width at the end.
Don't mix this up
Exam tip
Write it in the exam
Each point is worth about one mark. Write point 1 for a 1-mark question and keep adding points as the marks go up.
How CBSE asks it
- 1
Enough for 1 mark
The step deviation method is a fast way to find the mean of grouped data when class widths are equal.
- 2
Add for 2 marks
Example: If class width is 10 and a deviation is 20, then the coded deviation is 2.
- 3
Add for 3 marks
This method is used when the class intervals have the same width.
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