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Bounded and Unbounded Feasible Regions

A feasible region is bounded if it can be enclosed within a finite part of the plane; it is unbounded if it extends indefinitely in at least one direction.

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Student-friendly explanation

In a bounded feasible region, every linear objective function that is evaluated over the region has its optimum at a corner point. In an unbounded feasible region, an optimum may or may not exist. If the objective value can keep increasing in a maximization problem, no finite maximum exists. If it can keep decreasing in a minimization problem, no finite minimum exists.

How to write this in exams

  1. 1

    Start with the exact idea

    A feasible region is bounded if it can be enclosed within a finite part of the plane; it is unbounded if it extends indefinitely in at least one direction.

  2. 2

    Then show how to use it

    Identify whether the feasible region is enclosed. If bounded, apply the corner point table directly. If unbounded, compute candidate values at available vertices, then test whether the objective can improve further in the unbounded direction. State no finite optimum only when improvement is unlimited.

  3. 3

    Add one concrete example

    The constraints x >= 0, y >= 0, and x + y >= 4 form an unbounded feasible region in the first quadrant outside the line x + y = 4. A minimum of x + y is 4 on the boundary, but a maximum of x + y does not exist because x and y can grow without bound.

  4. 4

    Avoid this incomplete answer

    Writing no optimum merely because the feasible region is unbounded is a wrong application of the condition.

Definition

A feasible region is bounded if it can be enclosed within a finite part of the plane; it is unbounded if it extends indefinitely in at least one direction.

Example

The constraints x >= 0, y >= 0, and x + y >= 4 form an unbounded feasible region in the first quadrant outside the line x + y = 4. A minimum of x + y is 4 on the boundary, but a maximum of x + y does not exist because x and y can grow without bound.

Rule to remember

Condition for bounded region: feasible region is closed and enclosed by constraint boundaries. For unbounded region: corner point candidates must be checked against the direction in which the feasible region extends. If Z can improve indefinitely, the required optimum does not exist.

Memory hook

Unbounded means check direction, not automatically no answer.

Examples and method

Worked example

Minimize Z = x + y subject to x + y >= 6, x >= 0, y >= 0. The feasible region is unbounded in the first quadrant above the line x + y = 6. Boundary corner points are (6,0) and (0,6). Z(6,0)=6 and Z(0,6)=6. Since x + y cannot be less than 6 due to the constraint x + y >= 6, the minimum is 6 at every feasible point on the segment from (6,0) to (0,6).

Method to apply

Identify whether the feasible region is enclosed. If bounded, apply the corner point table directly. If unbounded, compute candidate values at available vertices, then test whether the objective can improve further in the unbounded direction. State no finite optimum only when improvement is unlimited.

Diagram support

A graph is useful when deciding boundedness. The open direction of the feasible region should be visible, and arrows may be used to show that the region extends indefinitely.

How CBSE asks it

Asked through short-answer reasoning, assertion-reason items, or as the final check in a graphical LPP where the region is open.

Avoid common mistakes

Common confusion

Students sometimes assume every unbounded feasible region has no solution. This is false because an unbounded region can still have a finite maximum or minimum depending on the objective function.

Common wrong answer

Writing no optimum merely because the feasible region is unbounded is a wrong application of the condition.

Exam tip

For an unbounded region, do not stop after listing corner values. Check whether better objective values are possible in the open direction of the feasible region.

Quick check

Can an unbounded feasible region have a finite minimum value? Give a brief answer.

Yes. For example, with x >= 0, y >= 0, x + y >= 4, the objective Z = x + y has minimum value 4 on the line x + y = 4.

Answer writing and exam use

1-mark answer

A feasible region is bounded if it can be enclosed within a finite part of the plane; it is unbounded if it extends indefinitely in at least one direction.

2-mark answer

A feasible region is bounded if it can be enclosed within a finite part of the plane; it is unbounded if it extends indefinitely in at least one direction. Condition for bounded region: feasible region is closed and enclosed by constraint boundaries. For unbounded region: corner point candidates must be checked against the direction in which the feasible region extends. If Z can improve indefinitely, the required optimum does not exist. The constraints x >= 0, y >= 0, and x + y >= 4 form an unbounded feasible region in the first quadrant outside the line x + y = 4. A minimum of x + y is 4 on the boundary, but a maximum of x + y does not exist because x and y can grow without bound.

3-mark answer

In a bounded feasible region, every linear objective function that is evaluated over the region has its optimum at a corner point. In an unbounded feasible region, an optimum may or may not exist. If the objective value can keep increasing in a maximization problem, no finite maximum exists. If it can keep decreasing in a minimization problem, no finite minimum exists. Condition for bounded region: feasible region is closed and enclosed by constraint boundaries. For unbounded region: corner point candidates must be checked against the direction in which the feasible region extends. If Z can improve indefinitely, the required optimum does not exist. Minimize Z = x + y subject to x + y >= 6, x >= 0, y >= 0. The feasible region is unbounded in the first quadrant above the line x + y = 6. Boundary corner points are (6,0) and (0,6). Z(6,0)=6 and Z(0,6)=6. Since x + y cannot be less than 6 due to the constraint x + y >= 6, the minimum is 6 at every feasible point on the segment from (6,0) to (0,6). Asked through short-answer reasoning, assertion-reason items, or as the final check in a graphical LPP where the region is open. Writing no optimum merely because the feasible region is unbounded is a wrong application of the condition.
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