Bounded and Unbounded Feasible Regions
A feasible region is bounded if it can be enclosed within a finite part of the plane; it is unbounded if it extends indefinitely in at least one direction.
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Student-friendly explanation
In a bounded feasible region, every linear objective function that is evaluated over the region has its optimum at a corner point. In an unbounded feasible region, an optimum may or may not exist. If the objective value can keep increasing in a maximization problem, no finite maximum exists. If it can keep decreasing in a minimization problem, no finite minimum exists.
How to write this in exams
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Start with the exact idea
A feasible region is bounded if it can be enclosed within a finite part of the plane; it is unbounded if it extends indefinitely in at least one direction.
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Then show how to use it
Identify whether the feasible region is enclosed. If bounded, apply the corner point table directly. If unbounded, compute candidate values at available vertices, then test whether the objective can improve further in the unbounded direction. State no finite optimum only when improvement is unlimited.
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Add one concrete example
The constraints x >= 0, y >= 0, and x + y >= 4 form an unbounded feasible region in the first quadrant outside the line x + y = 4. A minimum of x + y is 4 on the boundary, but a maximum of x + y does not exist because x and y can grow without bound.
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Avoid this incomplete answer
Writing no optimum merely because the feasible region is unbounded is a wrong application of the condition.
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Can an unbounded feasible region have a finite minimum value? Give a brief answer.
Yes. For example, with x >= 0, y >= 0, x + y >= 4, the objective Z = x + y has minimum value 4 on the line x + y = 4.
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